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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Mathematics
Chapter
Trigonometric Ratios & Identities

BITSAT 2010 · Mathematics · Trigonometric Ratios & Identities

If ( P(A B)=(2)/(3), P(A B)=(1)/(6) ) and ( P(A)=(1)/(3) ) then

If (P(A∪B)=23,P(A∩B)=16\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\frac{2}{3}, \mathrm{P}(\mathrm{A} \cap \mathrm{B})=\frac{1}{6}) and (P(A)=13\mathrm{P}(\mathrm{A})=\frac{1}{3}) then

Options

  1. AA and (B\mathrm{B}) are independent events
  2. BA and (B\mathrm{B}) are disjoint events
  3. CA and (B\mathrm{B}) are dependent events
  4. DNone of these

Correct answer

A. A and (B\mathrm{B}) are independent events

Step-by-step solution

(P(A∪B)=P(A)+P(B)−P(AB)\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{AB})) (\Rightarrow 23=13+P(B)−16⇒P(B)=12\frac{2}{3}=\frac{1}{3}+\mathrm{P}(\mathrm{B})-\frac{1}{6} \Rightarrow \mathrm{P}(\mathrm{B})=\frac{1}{2}) Now, (P(AB)=P(A)\mathrm{P}(\mathrm{AB})=\mathrm{P}(\mathrm{A})~ P(B),A\mathrm{P}(\mathrm{B}), \mathrm{A}) and (B\mathrm{B}) are independent events.
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