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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Mathematics
Chapter
Vector Algebra

BITSAT 2020 · Mathematics · Vector Algebra

If r and s arenon-zero constant vectors and the scalar b is chosen...

If r⃗\vec{r} and s⃗\vec{s} arenon-zero constant vectors and the scalar bb is chosen such that ∣r⃗+bs⃗∣|\vec{r}+b \vec{s}| is minimum, then the value of ∣bs⃗∣2+∣r⃗+bs⃗∣2|b \vec{s}|^{2}+|\vec{r}+b \vec{s}|^{2} is equal to

Options

  1. A2∣r⃗∣22|\vec{r}|^{2}
  2. B∣r⃗∣2/2|\vec{r}|^{2} / 2
  3. C3∣r⃗∣23|\vec{r}|^{2}
  4. D∣r⃗∣2|\vec{r}|^{2}

Correct answer

D. ∣r⃗∣2|\vec{r}|^{2}

Step-by-step solution

For minimum value ∣r⃗+bs⃗∣=0|\vec{r}+b \vec{s}|=0. Let r⃗\vec{r} and s⃗\vec{s} are anti-parallel so bs⃗=−r⃗∴∣bs⃗∣2+∣r⃗+bs⃗∣2=∣−r⃗∣2+∣r⃗−r⃗∣2=∣r⃗∣2b \vec{s}=-\vec{r}\therefore|b \vec{s}|^{2}+|\vec{r}+b \vec{s}|^{2}=|-\vec{r}|^{2}+|\vec{r}-\vec{r}|^{2}=|\vec{r}|^{2}
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