AIIMS2019PhysicsWork, Power and Energy
A body of mass 10^3 ~kg moving with speed 2 ~m ~s ⁻¹ collides with a body of mass 15 10^3 ~kg inelastically and sticks to it. Then loss in KE of the system will be
Options
- A1.875 ~kJ
- B15 ~kJ
- C10 ~kJ
- D5 ~kJ
Correct answer
A. 1.875 ~kJ
Step-by-step solution
aligned & Loss in KE = 1 2 M₁ M₂ (M₁+M₂ ) (u₁-u₂ )^2 & = 1 2 10^3 15 10^3 16 10^3 (2)^2 & = 1 2 15 10^3 16 4=1.875 ~kJ aligned