Two vessels A and B are of the same size and are at same temperature. A contains 1 g of hydrogen and B contains 1 g of oxygen. P_ A and P_B are the pressures of the gases in A and B respectively, then (P_A)/(P_B) is:

Correct answer: B. 16 n_ A =(1)/(2) mol, n_ B =(1)/(32) mol By ideal gas equation, P V=n R T P n P_ A P_ B = n_ A n_ B =(32)/(2)=16

BITSAT 2024Paper 1

BITSAT 2024 · Paper 1 · Physics · Kinetic Theory of Gases

Two vessels A and B are of the same size and are at same...

Two vessels

A

and

B

are of the same size and are at same temperature. A contains 1 g of hydrogen and

B

contains 1 g of oxygen.

\mathrm{P}_{\mathrm{A}}

and

P_B

are the pressures of the gases in

A

and

B

respectively, then

\frac{P_A}{P_B}

is:

B. $16$

\mathrm{n}_{\mathrm{A}}=\frac{1}{2} \mathrm{ mol}, \mathrm{n}_{\mathrm{B}}=\frac{1}{32} \mathrm{ mol}

By ideal gas equation,

P V=n R T \Rightarrow P \propto n\therefore \frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\mathrm{B}}}=\frac{\mathrm{n}_{\mathrm{A}}}{\mathrm{n}_{\mathrm{B}}}=\frac{32}{2}=16