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BITSAT 2018
Exam
BITSAT
Year
2018
Subject
Physics
Chapter
Thermal Properties of Matter

BITSAT 2018 · Physics · Thermal Properties of Matter

Steam at 100 ° C is passed into 1. 1kg of water contained in a...

Steam at 100°C100 ° C is passed into 1.1kg1. 1kg of water contained in a calorimoter of water equivalent to 0.2kg0. 2kg at 15°C15 ° C till the temperature of the calorimeter and its contents rises to 80°C80 ° C. The mass of steam condensed (in kgkg ) is

Options

  1. A0.1300. 130
  2. B0.0650. 065
  3. C0.2600. 260
  4. D0.1350. 135

Correct answer

A. 0.1300. 130

Step-by-step solution

(a) According to principle of calorimetry,
heat gained =~heat lost
Heat is lost by steam in two stages

(i) Change of state from steam at 100°C100 ° C to water at 100°C100 ° C is m×540.</p><p>(ii)m \times 540 .</p><p>(ii) To change water at100 ° Ctowateratto water at80 ° Cisism \times 1 \times \left(100 - 80\right),,~where mm is the mass of the steam condensed.

Total heat lost by steam is
m×540+m×20=m(540+20)m \times 540 + m \times 20 = m \left(540 + 20\right) = 560m

Heat gained by calorimeter and itscontentsis<br/>(1.1+0.2)its contents is<br />\left(1 . 1 + 0 . 2\right) \times \left(80 - 15\right) = 1 . 12 \times 65\text{cal}</p><p></p><p>⇒ 560m = 1 . 12 \times 65</p><p></p><p>⇒ m = \dfrac{1 . 12 \times 65}{560} =0 . 130kg

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