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BITSAT 2024Paper 2
Exam
BITSAT
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Waves and Sound

BITSAT 2024 · Paper 2 · Physics · Waves and Sound

The speed of sound in oxygen at S.T.P. will be approximately:...

The speed of sound in oxygen at S.T.P. will be approximately: (Given, R=8.3JK−1,γ=1.4)\left.\mathrm{R}=8.3 \mathrm{JK}^{-1}, \gamma=1.4\right)

Options

  1. A315m/s315 \mathrm{ m} / \mathrm{s}
  2. B333m/s333 \mathrm{ m} / \mathrm{s}
  3. C341m/s341 \mathrm{ m} / \mathrm{s}
  4. D325m/s325 \mathrm{ m} / \mathrm{s}

Correct answer

A. 315m/s315 \mathrm{ m} / \mathrm{s}

Step-by-step solution

At STP Temperature, T=273KT=273 \mathrm{ K} Molecular mass of oxygen, M=32×10−3kg\mathrm{M}=32 \times 10^{-3} \mathrm{ kg} Speed of sound is given by v=γRTM=1.4×8.3×27332×10−3=314.8541≃315m/s\mathrm{v}=\sqrt{\frac{\gamma \mathrm{RT}}{\mathrm{M}}}=\sqrt{\frac{1.4 \times 8.3 \times 273}{32 \times 10^{-3}}}=314.8541 \simeq 315 \mathrm{ m} / \mathrm{s}
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