A pendulum of mass 1 kg and length l=1 ~m is released from rest at angle =60^ . The power delivered by all the forces acting on the bob at angle =30^ will be ( . Take, .g=10 ~m / s ^2 )

Step-by-step solution

Power of tension =0 aligned & Power of m g=(m g)(v) 60^ & Here, v= 2 g h & and h=l ( 30^ - 60^ )=0.36 ~m & v= 2 10 0.36 & =2.68 ~m / s & Power =(m g)(v) 60^ & =(1 10)(2.68) 1 2 & =1.34 10=13.4 ~W aligned