A spherical ball of mass 20 kg is stationary at the top of a hill of height 100 m. It rolls down a smooth surface to the ground, then climbs up another hill of height 30 m and finally rolls down to a horizontal base at

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Correct answer: B. 40 m / s

Using conservation of energy, m(10 × 100)=m ((1)/(2) v^2+ 10 ×20) or (1)/(2) v^2=800 or v= 1600 =40 m/ s

A spherical ball of mass 20 kg is stationary at the top of a hill...

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