BITSAT2015PhysicsWork, Power and EnergyActual
An elastic string of unstretched length L and force constant k is stretched by a small length x . It is further stretched by another small length y. The work done in the second stretching is
Options
- A1 / 2 Ky ²
- B1 / 2 Ky (2 x + y )
- C1 / 2 ~K ( x ²+ y ² )
- D1 / 2 k ( x + y )²
Correct answer
B. 1 / 2 Ky (2 x + y )
Step-by-step solution
In the string elastic force is conservative in nature. W =- U Work done by elastic force of string, aligned W &=- ( U _ F - U _ i )= U _ i - U _ F W &= 1 2 k x ²- k 2 ( x + y )² &= 1 2 k x ²- 1 2 k ( x ²+ y ²+2 xy ) &= 1 2 k x ²- 1 2 k y ²- 1 2 kx ²- 1 2 k (2 xy ) &=- k x y - 1 2 k y ² aligned Therefore, the work done against elastic force W _ external =- W = K y 2 (2 x + y )