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BITSAT 2010

Exam: BITSAT
Year: 2010
Subject: Physics
Chapter: Work, Power and Energy

BITSAT 2010 · Physics · Work, Power and Energy

A long string is stretched by 2 cm and the potential energy is V ....

A long string is stretched by

2 \mathrm{ cm}

and the potential energy is

\mathrm{V}

. If the spring is stretched by

10 \mathrm{ cm}

, its potential energy will be

Options

A $\mathrm{V} / 25$
B $\mathrm{V} / 5$
C $5 \mathrm{ V}$
D $25 \mathrm{ V}$

Correct answer

D. $25 \mathrm{ V}$

Step-by-step solution

\quad V=\frac{1}{2} k(x)^{2}=\frac{1}{2} k(2)^{2}

or

k=\frac{2 V}{4}=\frac{V}{2} \mathrm{V}^{\prime}=\frac{1}{2} \mathrm{k}(10)^{2}=\frac{1}{2} \times\left(\frac{\mathrm{V}}{2}\right)(10)^{2}=25 \mathrm{ V}

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