BITSAT2009PhysicsWork, Power and EnergyActual
A chain of mass M is placed on a smooth table with 1 / n of its length L hanging over the edge. The work done in pulling the hanging portion of the chain back to the surface of the table is
Options
- AMgL / n
- BMgL / 2 n
- CMgL / n ²
- DMgL / 2 n ²
Correct answer
D. MgL / 2 n ²
Step-by-step solution
W = change in PE of COM of hanging part = M n g L 2 n = MgL 2 n ²