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COMEDK202510 May 2025Evening ShiftChemistryAlcohols Phenols and EthersActual

Identify X and Y formed in the following two reactions. (i) Decan-1-ol Jones reagent X (ii). Sodium salt of X NaOH / CaO , Y

Options

  1. AX = Decanoic acid Y = Nonane
  2. BX=1- Methoxy nonane Y= Octane.
  3. CX= Decan -2 -one Y= Octane
  4. DX = Octanoic acid Y = Heptane.

Correct answer

A. X = Decanoic acid Y = Nonane

Step-by-step solution

Decan-1-ol is a primary alcohol with the formula CH₃(CH₂)₈CH₂OH . Jones reagent ( CrO₃ / H₂SO₄ ) is a strong oxidizing agent that oxidizes primary alcohols directly to carboxylic acids. Therefore, the oxidation of decan-1-ol yields decanoic acid ( CH₃(CH₂)₈COOH ), which is X. The reaction of the sodium salt of a carboxylic acid with soda lime ( NaOH / CaO ) is known as decarboxylation. This process removes the carboxyl group as Na₂CO₃ and replaces it with a hydrogen atom, resulting in an alkane with one less carbon

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