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COMEDK202510 May 2025Evening ShiftChemistryAlcohols Phenols and EthersActual

Match the reaction in Column I with the major product formed given in Column II. ( array |l|l|l| & Column I- Reaction/conditions & & Column II- Product A & C ₆ H ₆ [ (ii) NaOH (iii) H^+ ] (i) Oleum & P & Pentan-2-ol. B & Butanal [ (ii) H ^+] (i) MeMgBr/ dry ether & Q & 2-Hydroxybenzoic acid. C & 2-Methylpropene [ (ii) H ₂ O ₂ / NaOH ] (i) B ₂ H ₆ & R & Phenol D & Phenol [ (ii) CO ₂, 400 ~K , 7 ~atm .] (i) NaOH & S &

Options

  1. AA = R B = P C = S D = Q
  2. BA = S B = R C = Q D = P
  3. CA = Q B = S C = P D = R
  4. DA = Q B = P C = S D = R

Correct answer

A. A = R B = P C = S D = Q

Step-by-step solution

Reaction A: Benzene reacts with oleum to form benzenesulfonic acid, which upon fusion with NaOH followed by acidification yields phenol. Thus, A = R. Reaction B: Butanal ( CH₃CH₂CH₂CHO ) reacts with methylmagnesium bromide ( MeMgBr ) followed by acidic workup to form a secondary alcohol. Specifically, CH₃CH₂CH₂CHO + CH₃MgBr CH₃CH₂CH₂CH(OMgBr)CH₃ H^+ CH₃CH₂CH₂CH(OH)CH₃ , which is pentan-2-ol. Thus, B = P. Reaction C: 2-Methylpropene ( CH₃C(CH₃)=CH₂ ) undergoes hydroboration-oxidation. The reaction follows anti-Marko

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