COMEDK2024Evening ShiftChemistryAminesActual
A compound having molecular formula C ₄ H ₁₁ N , reacts with CHCl ₃ in alcoholic KOH , on heating, to form a compound with a foul smell. Identify the optically active isomer of the compound which also shows the above reaction.
Options
- A2-Methylpropan-1-amine
- BN-Methylpropan-1-amine
- CButan-1-amine
- DButan-2-amine
Correct answer
D. Butan-2-amine
Step-by-step solution
The reaction of a compound with CHCl ₃ and alcoholic KOH to produce a foul-smelling substance (isocyanide) is the carbylamine test. This test is specific to primary amines ( R-NH₂ ). The molecular formula C ₄ H ₁₁ N corresponds to a saturated primary amine. The possible primary amine isomers are: 1. Butan-1-amine: CH ₃- CH ₂- CH ₂- CH ₂- NH ₂ 2. Butan-2-amine: CH ₃- CH ₂- CH ( NH ₂)- CH ₃ 3. 2-Methylpropan-1-amine: ( CH ₃)₂ CH - CH ₂- NH ₂ 4. 2-Methylpropan-2-amine: ( CH ₃)₃ C - NH ₂ Among these, we check for optic