According to Molecular orbital theory, which of the following is correct with respect to bond order?

Step-by-step solution

Bond order is calculated as N_b - N_a 2 , where N_b is the number of bonding electrons and N_a is the number of antibonding electrons. For N ₂ ( 14 electrons), the molecular orbital configuration is: _ 1s ^2 ^ * _ 1s ^2 _ 2s ^2 ^ * _ 2s ^2 _ 2p_x ^2 _ 2p_y ^2 _ 2p_z ^2 Bond order = 10 - 4 2 = 3 For N ₂^+ ( 13 electrons), the configuration is: _ 1s ^2 ^ * _ 1s ^2 _ 2s ^2 ^ * _ 2s ^2 _ 2p_x ^2 _ 2p_y ^2 _ 2p_z ^1 Bond order = 9 - 4 2 = 2.5 Thus, the bond order of N ₂^+ is less than that of N ₂ . For O ₂ ( 16 electron