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COMEDK20269 May 2026Morning ShiftChemistryChemical Bonding and Molecular StructureActual

The hybridisation of atomic orbitals of nitrogen in NO ₂^+ , NO ₃^- and NH ₄^+ are respectively

Options

  1. Asp^2, sp, sp^3
  2. Bsp, sp^2, sp^3
  3. Csp^2, sp^2, sp^3
  4. Dsp, sp^3, sp^2

Correct answer

B. sp, sp^2, sp^3

Step-by-step solution

For NO ₂^+ : The central nitrogen atom has 5 - 1 = 4 valence electrons. It forms two double bonds with two oxygen atoms. The number of bonds is 2 and there are no lone pairs. Steric number = 2 . Hybridisation is sp . For NO ₃^- : The central nitrogen atom forms three bonds with three oxygen atoms and has no lone pairs. Steric number = 3 . Hybridisation is sp^2 . For NH ₄^+ : The central nitrogen atom has 5 - 1 = 4 valence electrons. It forms four bonds with four hydrogen atoms and has no lone pairs. Steric number =

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