Given below are 4 molecular species/ions. Identify the species/ion which exhibits diamagnetic nature. [ A ]= N ₂⁺ [ B ]= O ₂⁻ [ C ]= B ₂ [ D ]= C ₂

Step-by-step solution

The molecular orbital configuration for each species is determined based on the number of electrons. For N₂⁺ (13 electrons): _ 1s ² , _ 1s ^ *2 , _ 2s ² , _ 2s ^ *2 , _ 2p_x ² , _ 2p_y ² , _ 2p_z ¹ Since there is one unpaired electron in the _ 2p_z orbital, it is paramagnetic. For O₂⁻ (17 electrons): _ 1s ² , _ 1s ^ *2 , _ 2s ² , _ 2s ^ *2 , _ 2p_z ² , _ 2p_x ² , _ 2p_y ² , _ 2p_x ^ *2 , _ 2p_y ^ *1 Since there is one unpaired electron in the _ 2p_y ^ * orbital, it is paramagnetic. For B₂ (10 electrons): _ 1s ² , _