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COMEDK20269 May 2026Evening ShiftChemistryChemical EquilibriumActual

An equilibrium mixture taken in 2litre vessel of the reaction: 2 SO ₂(g) + O ₂(g) 2 SO ₃(g) has 4 moles of SO ₂ , 3moles of O ₂ and 6moles of SO ₃ then the value of equilibrium constant (K_c) will be:

Options

  1. A0.75 L mol ⁻¹
  2. B0.15 mol L ⁻¹
  3. C1.5 L mol ⁻¹
  4. D15 mol L ⁻¹

Correct answer

C. 1.5 L mol ⁻¹

Step-by-step solution

The given equilibrium reaction is: 2 SO ₂(g) + O ₂(g) 2 SO ₃(g) The volume of the vessel is V = 2 L. The equilibrium concentrations of the gases are: [ SO ₂] = 4 2 = 2 mol L ⁻¹ [ O ₂] = 3 2 = 1.5 mol L ⁻¹ [ SO ₃] = 6 2 = 3 mol L ⁻¹ The expression for the equilibrium constant K_c is: K_c = [ SO ₃]^2 [ SO ₂]^2 [ O ₂] Substituting the equilibrium concentrations into the expression: K_c = (3)^2 (2)^2 (1.5) K_c = 9 4 1.5 = 9 6 = 1.5 L mol ⁻¹ Answer: 1.5 L mol ⁻¹

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