A Hydrocarbon [A] (molecular formula C ₃ H ₆ ) on reaction with Br ₂ / CCl ₄ gave [B]. When [B] is heated with 2 moles of alcoholic KOH , it gave compound [C]. 3 moles of Compound [C] when passed through red hot Iron tube forms [D]. Identify [D].

Step-by-step solution

The hydrocarbon [A] with molecular formula C ₃ H ₆ is propene, CH ₃- CH = CH ₂ . Reaction of propene with Br ₂ / CCl ₄ is an electrophilic addition reaction, which yields 1,2-dibromopropane as compound [B]: CH ₃- CH(Br) - CH ₂ Br . Heating [B] with 2 moles of alcoholic KOH results in dehydrohalogenation, which removes two molecules of HBr to form propyne, CH ₃- C CH , as compound [C]. Passing 3 moles of propyne through a red hot iron tube at high temperature induces cyclic trimerization, a reaction analogous to the