COMEDK2024Evening ShiftChemistryHydrocarbonsActual
Identify the products C, D and F formed in the following sets of reactions.
Options
- AC = p -nitrobromobenzene D = m -nitrobromobenzene F = o-nitrobromobenzene
- BC = o -nitrobromobenzene D = p -nitrobromobenzene F = m -nitrobromobenzene
- CC = o-nitrobromobenzene D = m -nitrobromobenzene F = p -nitrobromobenzene
- DC = m -nitrobromobenzene D = p -nitrobromobenzene F = o-nitrobromobenzene
Correct answer
B. C = o -nitrobromobenzene D = p -nitrobromobenzene F = m -nitrobromobenzene
Step-by-step solution
The reaction of benzene ( C₆H₆ ) with Br₂/FeBr₃ is an electrophilic aromatic substitution (bromination) which yields bromobenzene as product B. Bromobenzene (B) is then subjected to nitration using conc. HNO₃/H₂SO₄ . Since the bromine atom is ortho/para directing, the products C and D are o-nitrobromobenzene and p-nitrobromobenzene. In the second pathway, benzene is first nitrated with conc. HNO₃/H₂SO₄ to yield nitrobenzene as product E. Nitrobenzene is a deactivating group and is meta-directing. Subsequent bromina