COMEDK2015ChemistryIonic Equilibrium
The number of H ⁺ ions present in 1 ~mL of a solution whose pH is 13
Options
- A6.022 10¹⁰
- B6.022 10⁷
- C6.022 10²⁰
- D6.022 10²³
Correct answer
B. 6.022 10⁷
Step-by-step solution
pH =13 aligned [ H ]⁺ &=10^ - pH =10⁻¹³ ~mol I ⁻¹ 1000 ~mL solution contains &=10⁻¹³ 6.022 10²³ H ⁺ ions &=6.022 10¹⁰ H ⁺ ions aligned 1 ~mL solution contains = 6.022 10¹⁰ 1000 =6.022 10⁷ H ⁺ ions.