The pH of a mixture of 10 ~mL of 0.1 M H ₂ SO ₄ . 5 ~mL of 0.2 ~N HCl and 5 ~mL of 0.1 M Ca ( OH )₂ is

Step-by-step solution

Millimoles of H ⁺=N₁ V₁+N₂ V₂10 0.1 2+5 0.2=2+1=3 Millimoles of OH ⁻= N ₃ V₃=0.1 5 2=1 After neutralisation millimoles of H ⁺ left =3-1=2 Concentration of H ⁺= moles of H ⁺ volumes of solution = 2 10+5+5 = 2 20 =0.1 pH =- [ H ⁺ ]=- (10⁻¹ )=1