At 298 ~K , CO ₂ exerts a partial pressure of 0.835 bar. The amount of CO ₂ in millimoles dissolved in 0.9 L of water is: [ k _ H . for CO ₂ at 298 K is .1.67 10^3 bar ]

Step-by-step solution

Henry's Law states that the partial pressure of a gas is proportional to its mole fraction in the solution: P = K_H . Given P = 0.835 bar and K_H = 1.67 10^3 bar , the mole fraction of CO ₂ is calculated as: = P K_H = 0.835 1.67 10^3 = 0.5 10⁻³ = 5 10⁻⁴ . The mole fraction is defined as = n_ CO ₂ n_ CO ₂ + n_ H ₂ O . Since the amount of dissolved gas is very small, n_ CO ₂ + n_ H ₂ O n_ H ₂ O . The number of moles of water in 0.9 L is n_ H ₂ O = 900 g 18 g/mol = 50 mol . Therefore, n_ CO ₂ = n_ H ₂ O = 5 10⁻⁴ 50 =