Lead storage battery contains 4.25 M H ₂ SO ₄ which has a density of 1.24 ~g / ml . Calculate the molality of aqueous solution of H ₂ SO ₄ .

Step-by-step solution

Given molarity M = 4.25 mol/L and density d = 1.24 g/mL . The molar mass of H ₂ SO ₄ is 2 1 + 32 + 4 16 = 98 g/mol . Consider 1 L of the solution. The mass of the solution is 1000 mL 1.24 g/mL = 1240 g . The mass of the solute ( H ₂ SO ₄ ) in 1 L is 4.25 mol 98 g/mol = 416.5 g . The mass of the solvent (water) is 1240 g - 416.5 g = 823.5 g = 0.8235 kg . Molality m is defined as the number of moles of solute per kilogram of solvent: m = moles of solute mass of solvent in kg = 4.25 0.8235 5.161 mol/kg . Answer: 5.161