What is the amount of ice that separates out on cooling a solution containing 60 ~g of Ethylene glycol in 250 ~g of water to -9.3^ C ? K _ f of H ₂ O =1.86 ~K / m ; MM of ethylene glycol= 62 ~amu

Step-by-step solution

The molar mass of ethylene glycol is 62 g/mol . The number of moles of ethylene glycol is n = 60 62 0.9677 mol . The freezing point depression formula is T_f = K_f m , where m is the molality of the solution. Given T_f = 0 - (-9.3) = 9.3 K and K_f = 1.86 K kg/mol , we have 9.3 = 1.86 m . Solving for molality m , we get m = 9.3 1.86 = 5 mol/kg . Molality is defined as m = n W_ solvent in kg . Thus, 5 = 0.9677 W_ solvent . The mass of the remaining liquid water is W_ solvent = 0.9677 5 = 0.19354 kg = 193.54 g . The a