If the depression in freezing point of an aqueous solution containing a solute, which is neither dissociated nor associated, is a K with K _ f = b ~ K ~ k g ~ m o l ⁻¹ , what would be the elevation in boiling point ( X ) for this solution i

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If the depression in freezing point of an aqueous solution containing a solute, which is neither dissociated nor associated, is a K with K _ f = b ~ K ~ k g ~ m o l ⁻¹ , what would be the elevation in boiling point ( X ) for this solution if its K _ b = ~K ~K ~kg ~mol ⁻¹ ?

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Correct answer: B. X=c a b

The depression in freezing point is given by the formula T_f = K_f m , where m is the molality of the solution. Given T_f = a and K_f = b , we have a = b m , which implies m = a b . The elevation in boiling point is given by the formula T_b = K_b m , where K_b = c . Substituting the value of m obtained from the freezing point depression, we get T_b = c a b . Therefore, X = c a b . Answer: X=c a b

If the depression in freezing point of an aqueous solution containing a solute, which is neither dissociated nor associated, is a K with K _ f = b ~ K ~ k g ~ m o l ⁻¹ , what would be the elevation in boiling point ( X ) for this solution if its K _ b = ~K ~K ~kg ~mol ⁻¹ ?

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