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Vapour pressure of water at 293 ~K is 17.535 ~mm Hg . The vapour pressure of water at 293 ~K containing 25 ~g of glucose dissolved in 450 ~g of water is

Options

  1. A17.439 ~mm Hg
  2. B17.535 ~mm Hg
  3. C0.097 ~mm Hg
  4. D34.973 ~mm Hg

Correct answer

A. 17.439 ~mm Hg

Step-by-step solution

p^ -p_ s p^ = w₂ M₁ w₁ M₂ aligned 17.535-p_ s 17.535 &= 25 18 450 180 =5.55 10⁻³ 17.535-p_ s &=5.55 10⁻³ 17.535 p_ s &=17.535(1-0.00555) p_ s &=17.535 0.99445 p_ s &=17.437 ~mm Hg . aligned

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