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COMEDK2025ChemistryStructure of AtomActual

The de Broglie wavelength of a particle of mass 6.63 g moving with a velocity of 100 ~m ~s ⁻¹ is:

Options

  1. A10⁻²⁸ ~m
  2. B10⁻²⁵ ~m
  3. C10⁻³³ ~m
  4. D10⁻²³ ~m

Correct answer

C. 10⁻³³ ~m

Step-by-step solution

The de Broglie wavelength is given by the formula = h mv , where h is Planck's constant, m is the mass of the particle, and v is its velocity. Given values are: h = 6.63 10⁻³⁴ J s m = 6.63 g = 6.63 10⁻³ kg v = 100 m s ⁻¹ = 10² m s ⁻¹ Substituting these values into the formula: = 6.63 10⁻³⁴ (6.63 10⁻³) 10² = 6.63 10⁻³⁴ 6.63 10⁻¹ = 10^ -34 - (-1) = 10⁻³³ m Answer: 10⁻³³ ~m

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