Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK202510 May 2025Morning ShiftChemistryStructure of AtomActual

A certain orbital having 2 angular nodes and no radial nodes is:

Options

  1. A3s
  2. B3 p
  3. C3 d
  4. D2 p

Correct answer

C. 3 d

Step-by-step solution

The number of angular nodes in an orbital is given by the azimuthal quantum number l . The number of radial nodes in an orbital is given by the formula n - l - 1 , where n is the principal quantum number. Given that the orbital has 2 angular nodes, we have l = 2 . This corresponds to a d-orbital. Given that the orbital has 0 radial nodes, we have n - l - 1 = 0 . Substituting l = 2 into the radial node equation: n - 2 - 1 = 0 n = 3 . Therefore, the orbital is 3d . Answer: 3 d

Practice Structure of Atom on Quantrex Academy →

More from Structure of Atom

The frequency of photon which is emitted during a transition of electron of He ^+ ion from fifth energy level to third energy level will be: 2026Which of the following statement is correct ? 2026The wavelength of a particular electron transition for He ⁺ is 100 nm. The wavelength (in Å ) of H atom for the same transition is 2025The energy of second Bohr orbit of hydrogen atom is -3.4 eV. The energy of the fourth Bohr orbit of the He ⁺ ion will be 2025The work function of Cu is 7.68 10⁻¹⁹ ~J . If photons of wavelength 221 nm are made to strike the surface of the metal, the kinetic energy (in J) of the ejected electrons will be ( 2025In an element with atomic number (Z) 25 , the number of electrons with ( n+l ) value equal to 3 and 4 are x and y respectively. The value of (x+y) is 2025a , b , c , d are electromagnetic radiations. Frequencies of a , b are 3 10¹⁵ ~Hz , 2 10¹⁴ ~Hz , respectively, whereas wavelength of c, d are 400 ~nm , 750 ~nm , respectively. The 2025The number of electrons with magnetic quantum number, m _l=0 in the elements with atomic numbers Z=24 and Z=29 are respectively 2025 Full Structure of Atom list All COMEDK PYQs