Given below are 4 subatomic particles travelling with the same velocity "v". Which of them will have the shortest wavelength? [A]= Proton [B]= Neutron. [C]= Alpha particle. [D]= Electron.

Step-by-step solution

According to the de Broglie hypothesis, the wavelength of a particle moving with velocity v is given by = h mv , where h is Planck's constant and m is the mass of the particle. Since h and v are constant for all particles, the wavelength is inversely proportional to the mass m of the particle, i.e., 1 m . To find the shortest wavelength, we must identify the particle with the largest mass among the given options: Mass of electron ( m_e ) 9.1 10⁻³¹ kg. Mass of proton ( m_p ) 1.67 10⁻²⁷ kg. Mass of neutron ( m_n ) 1.