Ozone is formed by the reaction O _ 2(g) + O _ (g) O _ 3(g) , H = -107.2 kJ . Given O=O bond energy is 498.0 kJ mol ⁻¹ , the average bond energy of ozone is:

Step-by-step solution

The enthalpy of the reaction is given by the difference between the sum of bond energies of reactants and products. H = BE(reactants) - BE(products) For the given reaction O _ 2(g) + O _ (g) O _ 3(g) : H = BE(O=O) - 2 BE(O-O in O ₃) Substituting the given values: -107.2 = 498.0 - 2 BE(O-O in O ₃) 2 BE(O-O in O ₃) = 498.0 + 107.2 2 BE(O-O in O ₃) = 605.2 BE(O-O in O ₃) = 605.2 2 = 302.6 kJ mol ⁻¹ Answer: 302.6 kJ mol ⁻¹