Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK2012MathematicsApplication of Derivatives

Length of the subtangent at (a, a) on the curve y²= x² 2 a+x is equal to

Options

  1. A18 5
  2. B18 a 5
  3. C- 18 a² 5
  4. D18 a² 5

Correct answer

D. 18 a² 5

Step-by-step solution

y²= x² 2 a+x 2 y d y d x = 2 x 2 a+x - x² (2 a+x)² At (a, a), ( d y d x )_ (a, a) = 5 18 a Length of subtangent at (x₁, y₁ )= y₁ ( d y d x )_ (x₁, y₁ ) Length of subtangent at (a, a)= a ( d y d x )_ (a, a) = 18 a² 5

Practice Application of Derivatives on Quantrex Academy →

More from Application of Derivatives

Consider the quadratic equation a x^2+b x+c=0 , where 2 a+3 b+6 c=0 and let g(x)= a x^3 3 + b x^2 2 +c x . Statement-I : The given quadratic equation ax ^2+ bx + c =0 has at least 2025The difference between the absolute maximum and absolute minimum values of the function f(x)=2 x^3-15 x^2+36 x-30 on [-1,4] is 2025If f(x)=x e^ x(1-x) , x R , then f(x) is 2025The angle between the curves y ^2= x and x ^2= y at the point (1,1) is 2025If the tangent of the curve 4 y^3=3 a x^2+x^3 drawn at the point (a, a) forms a triangle of area 25 24 sq.units with the coordinate axes then a = 2025If the function f(x)= x- ^2 x is defined on the interval [- , ] , then f is strictly increasing in the interval 2025If the Lagrange's mean value theorem is applied to the function f(x)=e^x defined on the interval [1,2] and the value of c (1,2) is k , then e^ k-1 = 2025If the tangent to the curve x y+a x+b y=0 at (1,1) makes an angle Tan ⁻¹ 2 with X -axis, then ab a + b = 2025 Full Application of Derivatives list All COMEDK PYQs