COMEDK2023Morning ShiftMathematicsBinomial TheoremActual
The coefficient of x²⁹ in the expansion of (1-3 x+3 x^2-x^3 )¹⁵ is
Options
- A- 45 16
- B45 28
- C45 30
- D45 29
Correct answer
A. - 45 16
Step-by-step solution
The given expression is (1 - 3x + 3x^2 - x^3 )¹⁵ . Observe that 1 - 3x + 3x^2 - x^3 = (1 - x)^3 . Substituting this into the expression, we get ((1 - x)^3)¹⁵ = (1 - x)⁴⁵ . The general term in the binomial expansion of (1 - x)^ n is given by ^ n C_ r (1)^ n-r (-x)^ r = ^ n C_ r (-1)^ r x^ r . For the expansion of (1 - x)⁴⁵ , the term containing x²⁹ corresponds to r = 29 . The coefficient is ⁴⁵C₂₉ (-1)²⁹ = -⁴⁵C₂₉ . Since ⁴⁵C₂₉ = ⁴⁵C_ 45-29 = ⁴⁵C₁₆ , the coefficient is -⁴⁵C₁₆ . Answer: - 45 16