COMEDK2019MathematicsCircle
The point (5,-7) lies outside the circle
Options
- Ax²+y²-8 x=0
- Bx²+y²-5 x+7 y=0
- Cx²+y²-5 x+7 y-1=0
- Dx²+y²-8 x+7 y-2=0
Correct answer
A. x²+y²-8 x=0
Step-by-step solution
Let S₁: x²+y²-8 x=0 S₂: x²+y²-5 x+7 y=0 S₃: x²+y²-5 x+7 y-1=0 S₄: x²+y²-8 x+7 y-2=0 Now, at (5,-7) aligned &S₁=25+49-40=34>0 &S₂=25+49-25-49=0 &S₃=25+49-25-49-1=-1 < 0 &S₄=25+49-40-49-2=-17 < 0 aligned (5,-7) lies outside the circle S₁ .