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COMEDK2015MathematicsDefinite Integration

_ -1 ¹ (x²⁷ x+e^ x ) d x=

Options

  1. A2 e-1 e
  2. Be+1 e
  3. Ce- 1 e
  4. D1 e

Correct answer

C. e- 1 e

Step-by-step solution

aligned Let I &= _ -1 ¹ (x²⁷ x+e^ x ) d x & I= _ -1 ¹ x²⁷ x d x+ _ -1 ¹ e^ x d x aligned Since, f(x)=x²⁷ x is an odd function. _ -a ^ a f(x) d x=0 if f(x) is odd function So, I=0+ [e^ x ]_ -1 ¹=e- 1 e

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