COMEDK20269 May 2026Morning ShiftMathematicsDeterminantsActual
Given P = bmatrix 2 & & 1 1 & 2 & 2 1 & 3 & 3 bmatrix is the adjoint of a 3 3 matrix A and |A| = 3 , then the value of is:
Options
- A-8
- B-26
- C7
- D-25
Correct answer
A. -8
Step-by-step solution
Given P = adj (A) and A is a 3 3 matrix. We know that | adj (A)| = |A|^ n-1 , where n is the order of the matrix. Here, n = 3 and |A| = 3 . |P| = |A|³⁻¹ = |A|^2 = 3^2 = 9 Now, calculating the determinant of matrix P : |P| = vmatrix 2 & & 1 1 & 2 & 2 1 & 3 & 3 vmatrix Expanding along the first row: |P| = 2(2 3 - 2 3) - (1 3 - 2 1) + 1(1 3 - 2 1) |P| = 2(0) - (1) + 1(1) |P| = 1 - Equating the two values of |P| : 1 - = 9 = -8 Answer: -8