COMEDK20269 May 2026Evening ShiftMathematicsDifferential EquationsActual
The particular solution of the differential equation (x - y)(dx + dy) = (dx - dy) when y = -1 and x = 0 is
Options
- A| x - y x + y | = 1
- B|x - y| = x - y + 1
- C|x + y| = x - y + 1
- D|x - y| = x + y + 1
Correct answer
D. |x - y| = x + y + 1
Step-by-step solution
Given differential equation is (x - y)(dx + dy) = dx - dy Let x - y = u and x + y = w Differentiating, we get dx - dy = du and dx + dy = dw Substituting these in the given equation: u dw = du du u = dw Integrating both sides: du u = dw |u| = w + C Substituting back u = x - y and w = x + y : |x - y| = x + y + C Given that y = -1 when x = 0 : |0 - (-1)| = 0 - 1 + C 1 = -1 + C C = 1 Therefore, the particular solution is: |x - y| = x + y + 1 Answer: |x - y| = x + y + 1