If (x+y)+ (x+y)= (x+y) , then d² y d x² =

Step-by-step solution

Given that, (x+y)+ (x+y)= (x+y) On differentiating w.r.t. x , aligned & (x+y) (1+ d y d x )- (x+y) (1+ d y d x ) &= 1 (x+y) (1+ d y d x ) & (1+ d y d x ) (x+y)- (x+y)- 1 (x+y) =0 & 1+ d y d x =0 aligned Again differentiating w.r.t. ' x ' 0+ d² y d x² =0 d² y d x² =0