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COMEDK2015MathematicsDifferentiation

If y=| x|+| x| , then d y d x at x= 2 3 is

Options

  1. A1- 3 2
  2. B0
  3. C1 2 ( 3 -1)
  4. DNone of these

Correct answer

C. 1 2 ( 3 -1)

Step-by-step solution

We have, y=| x|+| x| At x= 2 3 , x is negative and x is positive. y=- x+ x d y d x = x+ x . d y d x |_ at x=2 / 3 = ( 2 3 )+ ( 2 3 ) = 3 2 - 1 2 = 3 -1 2

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