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The function f: X Y defined by f(x)= x is one-one but not onto if X and Y are respectively, is equal to

Options

  1. A[ - 2 , 2 ] and [-1,1]
  2. B[0, 2 ] and [-, 1,1]
  3. C[0, ] and [0,1]
  4. DR and R

Correct answer

B. [0, 2 ] and [-, 1,1]

Step-by-step solution

We have, f: X YX: domain and Y : codomain In one-one function, x₁ x₂f (x₁ ) f (x₂ ) In onto function, Range = domain . f(x)= x So, if X= [0, 2 ] and Y=[-1,1] For each value of x X and range =[0,1] , there exists a unique value for y Y Hence, function is one-one but not onto.

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