Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
COMEDK202510 May 2025Evening ShiftMathematicsLimitsActual

_ 2 1- ( 2 - ) is equal to

Options

  1. A-1
  2. B- 1 2
  3. C1
  4. D1 2

Correct answer

D. 1 2

Step-by-step solution

Let x = 2 - . As 2 , x 0 . Substituting = 2 - x , we have = ( 2 - x) = x and = ( 2 - x) = x . The limit becomes _ x 0 1 - x x x . Using the identity 1 - x = 2 ^2( x 2 ) , the expression is _ x 0 2 ^2( x 2 ) x x . Dividing numerator and denominator by x^2 , we get _ x 0 2 ( (x/2) x )^2 x x = _ x 0 2 ( 1 2 (x/2) x/2 )^2 x x . Since _ x 0 x x = 1 , the limit is 2 (1/2)^2 1 = 2 4 = 1 2 . Answer: 1 2

Practice Limits on Quantrex Academy →

More from Limits

If _ x 0 ( p 2x + 1 - 2x x + x ) = 1 then the value of ' p ' is 2026_ x 2 ( 1 - x x ) is equal to 2026The value of _ x 3 [ 1 x-3 + 9x 27-x^3 ] is: 2026_ x 0 (1 - 2x)(3 + x) x 4x is equal to: 2026If _ x 3 ( x^2 - ax - 3b x - 3 ) = 5 , then a + b = 2026If f(x) = cases x^2 - 1 & if x 2 x + 1 & if x < 2 cases , then _ x 1 f(x) + _ x 2 f(x) = 2026_ x 4 2 2 -( x+ x)^3 1- 2 x = 2025Let [x] denote the greatest integer less than or equal to x . Then _ x 2⁺ ( [x]^3 3 - [ x 3 ]^3 )= 2025 Full Limits list All COMEDK PYQs