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The value of _ x 0 3 x+e^ 2 x -1 x is equal to

Options

  1. A2
  2. B3
  3. C5
  4. D1

Correct answer

C. 5

Step-by-step solution

_ x 0 3 x+e^ 2 x -1 x Put x=0 0+e^0-1 0 ( 0 0 ) Using L'hospital's rule we can differentiate both Numerator and denominator separately _ x 0 3 3 x+2 e^ 2 x 1 Now put x=0 = 3 0+2 e^0 1 =3+2=5

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