The feasible region for the inequations x+2 y 4,2 x+y 6, x, y 0 is

Step-by-step solution

The given inequations are x+2 y 4,2 x+y 6 , x, y 0 . According to the inequtions x, y 0 , the feasible region be the first quadrant (including positive X and positive Y-axis). According to the inequation x+2 y 4 , the feasible region be the region above or on the line x+2 y=4 . According to the inequation 2 x+y 6 , the feasible region be the region below or on the line 2 x+y=6 . Now, the common feasible region will be the required feasible region. Thus, option (a) is correct.