In the group G= 1,5,7,11 under multiplication modulo 12, the solution of 7⁻¹ 12 (x 12 12 11)=5 is x=

Step-by-step solution

Given that, G= 1,5,7,11 is a group under multiplication module 12 . 7⁻¹=7 [ 7⁻¹ ₁₂ 7=1 ] array ll Now, & 7⁻¹ ₁₂ (x ₁₂ 11 )=5 & 7 ₁₂ (11 ₁₂ x )=5 & (7 ₁₂ 11 ) ₁₂ x=5 & 7 ₁₂ 11= remainder after dividing 77 from 12 & 5 ₁₂ x=5 & x=1 array