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COMEDK2024MathematicsProbability

A number n is choosen at random from S= 1,2 , 3, , 100 . Let A= n S: n is a perfect square , B= n S: n is odd number and C= n S: n is a even prime number then, correct order of their probability is

Options

  1. AP(A) P(B) P(C)
  2. BP(A) P(B) P(C)
  3. CP(B) P(A) P(C)
  4. DP(A) P(C) P(B)

Correct answer

C. P(B) P(A) P(C)

Step-by-step solution

Total number of outcomes =100 Total number of perfect square =10 Total odd number =50 Total number of even prime number =1 aligned & P(A)= 10 100 = 1 10 =0.1 & P(B)= 50 100 = 1 2 =0.5 & P(C)= 1 100 =0.01 & P(B) P(A) P(C) aligned

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