COMEDK2024MathematicsSequences and SeriesActual
The sum of first three terms of a geometric progression is 16 and the sum of next three terms is 128 . The sum to n terms of the geometric progression is
Options
- A8 3 (3^n-1 )
- B8 3 (2^n-1 )
- C16 7 (3^n-1 )
- D16 7 (2^n-1 )
Correct answer
D. 16 7 (2^n-1 )
Step-by-step solution
Let the first term be a and common ratio be r . a(1+r+r^2) = 16 ... (1) ar^3(1+r+r^2) = 128 ... (2) Dividing (2) by (1): r^3 = 8 r = 2 Substituting in (1): a(1+2+4) = 16 a = 16 7 S_n = a(r^n-1) r-1 = 16 7 (2^n-1) 1 = 16 7 (2^n-1)