Let 'P' be the mean deviation of the first five odd natural numbers about their mean and 'Q' be the mean deviation of the first five prime numbers about their mean. The Q-P=

Step-by-step solution

The first five odd natural numbers are 1, 3, 5, 7, 9 . Mean x _P = 1 + 3 + 5 + 7 + 9 5 = 25 5 = 5 . Mean deviation P = |1-5| + |3-5| + |5-5| + |7-5| + |9-5| 5 = 4 + 2 + 0 + 2 + 4 5 = 12 5 = 2.4 . The first five prime numbers are 2, 3, 5, 7, 11 . Mean x _Q = 2 + 3 + 5 + 7 + 11 5 = 28 5 = 5.6 . Mean deviation Q = |2-5.6| + |3-5.6| + |5-5.6| + |7-5.6| + |11-5.6| 5 = 3.6 + 2.6 + 0.6 + 1.4 + 5.4 5 = 13.6 5 = 2.72 . Therefore, Q - P = 2.72 - 2.4 = 0.32 . Answer: 0.32