COMEDK2024MathematicsStraight Lines
If the equation of pair of lines y=m₁ x and y=m₂ x can be written as (y-m₁ x ) (y-m₂ x )=0 . Then the equation of pair of the angle bisector of the lines 5 x^2+2 x y+3 y^2=0 is
Options
- Ax^2-4 x y-y^2=0
- Bx^2-2 x y-y^2=0
- Cx^2-8 x y-y^2=0
- Dx^2-6 x y-y^2=0
Correct answer
B. x^2-2 x y-y^2=0
Step-by-step solution
If L a x^2+b y^2+2 h x y=0 Then equation of pair of angle bisector is x^2-y^2 a-b = x y h Equation of pair of angle bisector of 5 x^2+2 x y+3 y^2=0 is array rlrl & & x^2-y^2 5-3 & = x y 1 & & x^2-y^2 & =2 x y & x^2-2 x y-y^2 & =0 array