The lines x-1 2 = y-4 4 = z-2 3 and 1-x 1 = y-2 5 = 3-z a are perpendicular to each other, then a equals to

Step-by-step solution

Let L₁: x-1 2 = y-4 4 = z-2 3 and L₂= 1-x 1 = y-2 5 = 3-z a the line L₂ can be written as x-1 -1 = y-2 5 = z-3 -a Now, the DR's of lines L₁ and L₂ are (2,4,3) and (-1,5,-a) respectively. Since, L₁ and L₂ are perpendicular to each other. array lrl & 2(-1)+4)(5)+3(-a)=0 & -2+20-3 a=0 & -3 a=-18 a=6 array