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The general solution of 2 4 x+ ^2 2 x=0 is

Options

  1. Ax= n 2 ⁻¹ ( 1 5 )
  2. Bx= n 4 + (-1)^n 4 ⁻¹ ( 1 5 )
  3. Cx = n 2 1 4 ⁻¹ (- 1 3 )
  4. Dx= n 2 ⁻¹ ( 1 5 )

Correct answer

C. x = n 2 1 4 ⁻¹ (- 1 3 )

Step-by-step solution

2 4x + ^2 2x = 0 Using 4x = 1 - 2 ^2 2x ^2 2x = 1 - 4x 2 : 2 4x + 1 - 4x 2 = 0 4 4x + 1 - 4x = 0 3 4x = -1 4x = - 1 3 General solution: 4x = 2n ⁻¹ (- 1 3 ) x = n 2 1 4 ⁻¹ (- 1 3 )

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